Question

If a train 110m long passes a telegraph pole in 3 seconds, then the time taken by it to cross railway platform 165m long is

Answer 1

Step-by-step explanation:

Speed = distance / time

s = 110/3 ms⁻¹

Equating with second equation:

165/x = 110/3 (cross-multiplication)

x = (165x3)/110

x = 495/110

x = 99/22

x = 9/2

x = 4.5 seconds

Answer 2

Answer:

According to the given problem statement;

Distance covered by train in 3 seconds = 110 meters

Then the speed of train can be calculated by the relation;

Speed = distance / time

Speed = 110 / 3 m/s = 36.67 m/s

So the train moves with a speed of 36.67 meters per second.

Train crosses a platform of length = 165 meters

Time taken to cross the platform = ?

Total length of train and platform= 165 + 110 meters = 275 meters

Repeating the relation for velocity;

velocity = distance / time

Time = distance / velocity = 275 / 36.67

Time = 7.5 seconds

When a train 110 m long passes a telegraph pole in 3 seconds, then the time taken by it to cross a railway platform 165 m long is 7.5 seconds.