Question

If a train accelerating uniformly at 5m/sec attains a velocity of 90km/h. After the start, find its displacement and time for which it accelerate

Answer 1

time=t
final velocity=v
initial velocity=u=0
acceleration=a=5m/sec
90×1000/3600=25m/s
final velocity=initial velocity+acceleration×time
25m/s=0+5m/s²×time
25/5=time
5s=time
displacement=ut+1/2at²
displacement=0+1/2×5×(5s)²
displacement=1/2×5×25
displacement=1/2×125
displacement=62.5m