Question

if a train accelerating uniformly5m/s2 attains velocity of90km/h. after the starting,find it's displacement and time displacement and time for which if accelerates

Answer 1

90km/h=90×5/18m/s=25m/s
v=u+at
90=0+5t
t=18s.
the distance travelled in 18 seconds.
s=ut+1/2at^2.
s=0×18+1/2×5×18×18
s=1/2×18×18
s=9×18
s=162m.
means the displacement is 162m.