If a train accerlating uniformly at 5m / s square attains a velocity of 90km / h. after the start find it's displacement and time for which if accerlates
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here is the answer to ur question
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v = u + at
if u = 0
then v = at
90 km/ h = 5 m/ s^2 × t
90 × 1000/ 60 × 60m/ sec
= 5× t
t = 2sec
we know that,
displacement = acceleration × time
d = 5 × 2
d = 10 m / sec
if u = 0
then v = at
90 km/ h = 5 m/ s^2 × t
90 × 1000/ 60 × 60m/ sec
= 5× t
t = 2sec
we know that,
displacement = acceleration × time
d = 5 × 2
d = 10 m / sec
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