if a train crosses a point in 27/2sec, moving with a speed of 30km/h, length of the train is
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Answered by
3
distance = speed × time
length of the train = (30×5/18)× 27/2
= (150/18) × (27/2)
=(150/2) × (3/2)
=450/4
=112.5 m
length of the train = (30×5/18)× 27/2
= (150/18) × (27/2)
=(150/2) × (3/2)
=450/4
=112.5 m
Answered by
0
Answer:
112.5 Meter
Step-by-step explanation:
Given that,
A train crosses a point in 27/2 sec.
so, time ( t ) = 27/2 sec
speed of the train ( v ) = 30 km/h = ( 30 * 1000 ) m/h
= 30000 / ( 60 * 60 ) m/s
= ( 50 / 6 ) m/s
We know that,
Distance = speed * time
Distance = ( 50 / 6 ) * ( 27 / 2 ) m
= 12.5 * 9 m
= 112.5 m
Hence the length of train = 112.5 Meter.
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