Question

If a train moves with final velocity of 6ms-¹ and with an uniform acceleration -0.2 ms-² in 4 seconds. calculate the initial velocity of the train ​

Answer 1

Given :-

• Final velocity (v) = 6 ms-¹
• Acceleration (a) = -0.2 ms-²
• Time (t) = 4 sec

To Find :-

• Initial velocity of the train.

Solution :-

Applying 1st eqn of motion,

⭐ v = u + at

Where,

• v = Final velocity
• u = Initial velocity
• a = Acceleration
• t = Time

[ Put the values ]

$\longrightarrow$ 6 = u + -0.2 × 4

$\longrightarrow$ 6 = u - 0.8

$\longrightarrow$ -u = -6 - 0.8

$\longrightarrow$ -u = -6.8

$\green\longrightarrow$ u = 6.8 ms-¹

Hence,

• The initial velocity of the train is 6.8 ms-¹.

For information:

• S = ut + 1/2 at²
• v² = u² + 2as