Question

If a train runs at 40 kmph it reaches its destination late by 11 minutes. But if it runs at
50 kmph it is late by 5 minutes only. Find the distance to be covered by the train.
forect One third of the total number is​

Answer 1

Answer:

first try to answer if you not get answer I will answer it

Answer 2

answer

Let the normal time be ‘t’ hours to reach the destination at a distance of ‘x’ km

If the train runs at 40 km/hr it reaches the destination , the train is late by 11 minutes , i.e late by 11/60 hours, Ot it takes t + 11/60 hours. Then

Distance = Speed x time

i . e x = 40 *(t+11/60) ……….(1)

Again when the train runs at a speed of 50 km/he , it reaches 5 minutes late. So we have the following equation as well

i.e. x = 50 * ( t+ 5/60) …………. (2)

Equating equation (1) and (2), now we have this expression

40*(t+11/60) = 50(t+5/60)

4(t+11/60) = 5(t+5/60)

4t + 11/15 = 5t + 5/12

t = 11/15 - 5/12

t = (132 - 75)/180

t = 57/180

t = (57/180)*60 minutes

t = 19 minutes