if a train runs at 40 kmph it reaches its destination late by 11 minutes.but if it runs at 50 kmph it is late by 5 minutes only.find the distance to be covered by the train
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let the correct tym of arrival be t
given train moves with 40kmph
let the distance covered is x km
tym taken is x/40
this tym is 11 minutes late then the correct one so t = x/40+11 .......(1)
similarly another eq is t = x/50 +5 ......(2)
equating (1) &(2)
x/40 +11 = x/50+5
x/50 -x/40 =6
40x-50x/200 = 6
-10x/200 =6
x is -120 km
but since distance cant be -ve
distance covered is 120 km
given train moves with 40kmph
let the distance covered is x km
tym taken is x/40
this tym is 11 minutes late then the correct one so t = x/40+11 .......(1)
similarly another eq is t = x/50 +5 ......(2)
equating (1) &(2)
x/40 +11 = x/50+5
x/50 -x/40 =6
40x-50x/200 = 6
-10x/200 =6
x is -120 km
but since distance cant be -ve
distance covered is 120 km
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