Question

if a train runs at 40kmph it reaches its destination late by 11 minutes , but if it runs at 50 kmph it is late by 5 minutes only. find the distance to be covered by the train. please answer this question with explanation​

Answer 1

Answer and Step-by-step explanation:

Let the normal time be ‘t’ hours to reach the destination at a distance of ‘x’ km

If the train runs at 40 km/hr it reaches the destination , the train is late by 11 minutes , i.e late by 11/60 hours, Ot it takes t + 11/60 hours. Then

Distance = Speed x time

i . e x = 40 *(t+11/60) ……….(1)

Again when the train runs at a speed of 50 km/he , it reaches 5 minutes late. So we have the following equation as well

i.e. x = 50 * ( t+ 5/60) …………. (2)

Equating equation (1) and (2), now we have this expression

40*(t+11/60) = 50(t+5/60)

4(t+11/60) = 5(t+5/60)

4t + 11/15 = 5t + 5/12

t = 11/15 - 5/12

t = (132 - 75)/180

t = 57/180

t = (57/180)*60 minutes

t = 19 minutes

Answer 2

Answer:

• The distance to be covered by the train is 20 km

Given:

• If a train runs at 40 km/hr it reaches it's destination late by 11 minutes

• If it runs at 50 km/hr it is late by 5 minutes

To find:

• The distance to be covered by the train.

Solution:

Let train take x hr to reach the destination.

11 minute = 11/60 hr and

5 minute = 5/60 hr

Distance = Time × Speed

It's late means it take more time than the required time.

According to the first condition.

Distance = ( x + 11/60 ) × 40

=> Distance = 40x + 22/3...(1)

According to the second condition.

Distance = ( x + 5/60 ) × 50

=> Distance = 50x + 25/6...(2)

From equation (1) and (2), we get

=> 40x + 22/3 = 50x + 25/6

=> 10x = 22/3 - 25/6

=> 10x = (44-25)/6

=> 10x = 19/6

=> x = 19/60

Substituting in equation (1), we get

=> Distance = 40( 19/60 ) + 22/3

=> Distance = 38/3 + 22/3

=> Distance = 60/3

=> Distance = 20 km

The distance to be covered by the

train is 20 km