if a train runs at a speed of 100km per hour and has to reach a station 1000 km away and there are 5 stations to stop in the middle at the first station 5 minutes and at every station the time increases by 2 minutes. If the train starts at 6am then at what time will it stop on the fifth station?
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Step-by-step explanation:
Given Train starts at the same time.
Hence, Time remains constant.
Speed of Train 'T1' be 'S1' = 40 km\hr
Speed of Train 'T2' be 'S2' = 45 km\hr
Let X be the distance at which trains meet.
Train T2 travels X+40 km more than Train T1
According to the formula.
Speed=
Time
Distance
Time=
45
X+40
Time=
40
X
From above two equations.
40
X
=
45
X+40
45×X=40×X+40×40
5×X=1600
=320 km
Distance between two Stations = Distance at which train T1 meet + Distance at which Train T2 meet + Distance train T2 travels
= 320+320+40
= 680
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