if a train travels (30a square +15a-10) km in 10 hours ,what is its average speed?
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if a train travels (30a square +15a-10) km in 10 hours ,what is its average speed?
solution : distance travelled by train, S = (30a² + 15a - 10)km
= 5(6a² + 3a - 2) km
time taken by train to travel distance S = T = 10 hours.
we know,
speed = distance travelled/time taken
= S/T
= 5(6a² + 3a - 2)/10
= (6a² + 3a - 2)/2
= 3a² + (3/2)a - 1
hence, average speed of train is, 3a² + (3/2)a - 2
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if a train travels (30a square +15a-10) km in 10 hours ,what is its average speed?
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