if a train travels a distance of 340 km in 3(5/4) hours find the speed at which is it was travelling
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Let r be the speed of first train.
And r+5 be the speed of other train.
The distance first train travels in 2 hours is =2r
The distance other train travels in 2 hours is (r+5)×2=2(r+5)
Now we know that the distance the first train travels (2r) plus the distance the other train travels 2(r+5) equals 340−30=310.
So, 2r+2(r+5)=310
⇒2r+2r+10=310
⇒4r=300
⇒r=75
Thus, speed of first train is 75 mph.
Therefore, the speed of other train is r+5=75+5=80 mph.
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