Question

If a train with a speed of 60 km/hr. ,crosses a
pole in 30 seconds. The
length of the train( in meter) ​

Answer 1

Answer:

500 metres.

Explaination :

The length of pole is considered as negligible i.e. = 0

i.e. When a train crosses a pole, it covers the distance equal to its length.

the time taken by the train = 30 seconds

and speed = 60 km/h

then the length of the train

=60 kmph×30 seconds

=60×518×30 metres

=10×53×30= 500 metres.

HOPE IT HELPS!

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Answer 2

Answer:-

The length of the train is equal to the distance it traveled after 30 seconds. The distance traveled is the product of the train's speed and the elapsed time. The train's speed in km/h much first be converted to meters per second.

First let's convert the train's speed

Train's speed = 60 km/h

$Train's \: speed = \frac{60,000 \: m}{3,600 \: s}$

$Train's \: speed = \frac{50}{3} \: m/s$

Let's solve for the distance traveled in 30 seconds

Distance traveled = Train's speed × elapsed time

$Distance \: traveled = \frac{50}{3} \: m/s \times 30s$

$Distance traveled = \frac{1500}{3} \: m$

Distance traveled = 500 m

Length of the train = distance traveled

Length of the train = 500 m

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