If a transversal intersects two lines such that the bisectors of a pair of corresponding angles are parallel, then
prove that the two lines are also parallel.
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The transversal AD intersects the two lines PQ and RS at points B and C respectively. BE is the bisector of ∠ABQ and CF is the bisector of ∠BCS.
As, BE is the bisector of ∠ABQ, then,
∠ABE=
1/2
∠ABQ
In the same way,
∠BCF=
1/2
∠BCS
Since BE and CF are parallel and AD is the transversal, therefore, by corresponding angle axiom,
∠ABE=∠BCF
1/2
∠ABQ=
1/2
∠BCS
∠ABQ=∠BCS
Therefore, by the converse of corresponding angle axiom,
PQ∥RS.
Step-by-step explanation:
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