if a transversal intersects two lines such that the bisector of a pair of alternate interior angles are parallel then prove that the two lines are parallel
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Step-by-step explanation:
The transversal AD intersects the two lines PQ and RS at points B and C respectively. BE is the bisector of ∠ABQ and CF is the bisector of ∠BCS.
As, BE is the bisector of ∠ABQ, then,
∠ABE=
2
1
∠ABQ
In the same way,
∠BCF=
2
1
∠BCS
Since BE and CF are parallel and AD is the transversal, therefore, by corresponding angle axiom,
∠ABE=∠BCF
2
1
∠ABQ=
2
1
∠BCS
∠ABQ=∠BCS
Therefore, by the converse of corresponding angle axiom,
PQ∥RS.
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