Question

If A travels to his school from his house at the speed of 3 km/h, then he reaches the school 5 minutes late. If he travels at the speed of 4 km/h, he reaches the school 5 minutes earlier than school time. The distance of his school from his house is:
A.1 km
B.2 km
C.3 km
D.4 km

Answer 1

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Let the distance between school and home be x km.
The difference of time when A goes school to school with these two different speed is 10 min = 10/60 hour. 
Now, 

$\frac{x}{3} - \frac{x}{4} = 10/60$

$Or, \frac{x}{12} = \frac{1}{6}$

$Or, x = \frac{12}{6}$

= 2 km.

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