Question

If a triangels base 4/3 cm and perimeter is 62/16 cm. Then what is the length of his two equal arm?

Answer 1

Let the two equal unknown arms be x.

Then,

$x + x + \frac{4}{3} = \frac{62}{16} \\ \\ 2x + \frac{4}{3} = \frac{62}{16} \\ \\ 2x = \frac{62}{16} - \frac{4}{3} \\ \\ 2x = \frac{186 - 64}{48} \\ \\ 2x = \frac{122}{48} \\ \\ x = \frac{ \frac{122}{48} }{2} \\ \\ x = \frac{122 \times 2}{48 \times 1} = \frac{122}{24} = \frac{61}{12}$

${ \huge {\green{Hence, \: \: the \: \: two \: \: unknown \: \: equal \: \: sides \: \: of \: \: triangle \: \: was \: \: \frac{61}{12} \: \: and \: \: \frac{61}{12} }}}$