if a triangle ABC,cot A.cotb+cotb.cotc+cotc.cota is
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Answer:
Correct option is
B
1
In ΔABC , A+B+C=180
∘
⟹A+B=180
∘
−C
⟹cot(A+B)=cot(180
∘
−C)
⟹
cotA+cotB
cotA.cotB−1
=−cotC
⟹cotA.cotB−1=−cotA.cotC−cotB.cotC
⟹cotA.cotB+cotB.cotC+cotC.cotA=1
Hence, answer is option-(B).
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