Question

if a triangle ABC
is right angled at A then show that

r1+r3=r1-r​

Answer 1

r1 – r = r2 + r3 ∆/(s - a) - ∆/s = ∆/(s - b) + ∆/(s - c) ⇒ ∆a/s(s - a) = ∆a/((s - b)(s - c)) ⇒ s(s - a) = (s - b)(s - c) ⇒ tan(A/2) = √(((s - b)(s - c))/s(s - a)) = 1 ⇒ A = 90º

Answer 2

Answer:

I don't know sorry about that