Question

if a triangle ABC is right angled at C than the value of sec A+B​

Answer 1

Answer:

here sec(a+b)

=sec90

(a+b+c=180)

a+b=90

Answer 2

Answer:

Given:ABC is a right angle triangle.

Therefore angle C= 90°

To find: sec(A+B)=?

Solution:

By angle sum property in triangle ABC .

A+B+C=180°

A+B+90°=180°

A+B=180-90

A+B=90°

By multiplying both sides by sec.

sec A+B=sec 90°

(sec90° =not defined )

Therefore,sec A+ B= not defined or infinity.