if a triangle ABC right angled at c ,then find the value of sec(b+c) A-0 B-1. C-2/√3. D-not defined ......plz guys help me.......
Answers
Answered by
3
Answer:
d- not defined
Step-by-step explanation:
the triangle is right angled at c have no relation with the sec(b+c)
Answered by
0
Answer:
option C = -2/√3
Step-by-step explanation:
triangle ABC right angled at c
=> ∠c = 90°
=> 180° > ∠b + ∠c > 90°
Sec180° > Sec (b + c) > Sec90°
Sec (b + c) ≠ 0 as Secθ ≥ 1 or Secθ ≤ -1
Sec (b + c) = - 1 for 180° but b + c < 180°
Sec (b + c) = not defined for 90° but b + c > 90°
Hence from given option only possible value is
-2/√3 = Sec 150°
=> b + c = 150° ( which is only possible)
So out of given option correct answer is
option C = -2/√3
( not defined & can not be find are different things)
if there would have been option could not be find then that could be the answer but do not confuse with not defined
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