Question

if a triangle ABC right angled at c ,then find the value of sec(b+c) A-0 B-1. C-2/√3. D-not defined ......plz guys help me.......​

Answer 1

Answer:

d- not defined

Step-by-step explanation:

the triangle is right angled at c have no relation with the sec(b+c)

Answer 2

Answer:

option C  = -2/√3

Step-by-step explanation:

triangle ABC right angled at c

=> ∠c = 90°

=>  180° > ∠b + ∠c > 90°

Sec180° > Sec (b + c)  > Sec90°

Sec (b + c) ≠ 0   as  Secθ ≥ 1  or Secθ ≤ -1

Sec (b + c) = - 1  for 180°  but b + c < 180°

Sec (b + c) = not defined for 90°  but b + c > 90°

Hence from given option only  possible value is

-2/√3   = Sec 150°

=> b + c = 150°  ( which is only possible)

So out of given option correct answer is

option C  = -2/√3

( not defined  & can not be find are different things)

if there would have been option could not be find then that could be the answer but do not confuse with not defined