Question

If a triangle and a parallelogram are on the same base and between the same parallels then prove that the area of thr triangle is equal to half the area of parallelogram

Answer 1

Answer:

Step-by-step explanation:

In the adjoining figure, parallelogram ABCD and ∆ABD are on the same base AB and between the same parallels AF and DC.

Therefore, area of ∆ABD = 1/2 area of parallelogram ABCD

= 1/2 (AB × AE);

[Since, DE is the altitude of parallelogram ABCD]

Here, AB is the base and AE is the height of ∆ABD.

Answer 2

Step-by-step explanation:

Area of parlgrm= b*h

Area of tria' = (1/2)b*h

so area of tra

= half of area of parlgrm