Question

if a triangle and a parallelogram are on the same base and between the same parrels then prove that the area of the triangle equal to half the area of parrellogram ​

Answer 1

Step-by-step explanation:

In the adjoining figure, parallelogram ABCD and ∆ABD are on the same base AB and between the same parallels AF and DC.

Triangle and Parallelogram on Same Base and between Same Parallels

Therefore, area of ∆ABD = 1/2 area of parallelogram ABCD

= 1/2 (AB × AE);

[Since, DE is the altitude of parallelogram ABCD]

Here, AB is the base and AE is the height of ∆ABD