Math, asked by gowthamchoudary06, 2 months ago

if a triangle and a parallelogram are on the same base and between same parallels,then what is the ratio of the area of the area of the triangle to the area of parallelogram?​

Answers

Answered by MyDream56
3

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Answered by Kizzie82
0

Answer:

Ratio:1:2... Ar.(ABP) =1/2ar.(ABCD)

Step-by-step explanation:

Construction:Join DP

Let DM perpendicular to AB and PN perpendicular to AB

Proof:for parallelogram ABCD:

Height=DM...Base=AB

Ar. (ABCD) =Base × Height

=AB×DM

for triangle APB

Height =PN...Base=AB

Ar. (APB) =1/2 ×AB×PN

as opposite sides of parallelogram are equal..PN=DM

Let's substitute DM on the place of PN

From and

Ar. (APB) =1/2 ar.(ABCD)

Hope it Helps...

Thanks

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