if a triangle and a parallelogram are on the same base and between same parallels,then what is the ratio of the area of the area of the triangle to the area of parallelogram?
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Answer:
Ratio:1:2... Ar.(ABP) =1/2ar.(ABCD)
Step-by-step explanation:
Construction:Join DP
Let DM perpendicular to AB and PN perpendicular to AB
Proof:for parallelogram ABCD:
Height=DM...Base=AB
Ar. (ABCD) =Base × Height
=AB×DM ➊
for triangle APB
Height =PN...Base=AB
Ar. (APB) =1/2 ×AB×PN ➋
as opposite sides of parallelogram are equal..PN=DM
Let's substitute DM on the place of PN
From ➊ and ➋
Ar. (APB) =1/2 ar.(ABCD)
Hope it Helps...
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