If a triangle and parallelogram are on the same base and between same parallel prove that the area of triangle is equal to the half of the area of the parallelogram
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hey mate we know that the formula for area of triangle is 1/2* length *base and the area of parallelogram is Length*base
as in this case both triangle and parallelogram have same length and same base.
So, IN this case area of triangle is half to that of area of parallelogram
Step-by-step explanation:
Area of triangle =1/2(area of parallelogram )
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hey dude it's simple
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