if a triangle and parallelogram are on the same base and between the same parallels then prove that area of triangle is equal to half of the area of parallelogram
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Divide the parallelogram into two triangles. Congurent the two given triangle. The congurent triangle implies that there area are same. Then Area of 1st triangle + Area of 2nd triangle = Parallelogram.
Which is :- 2*Area of any one triangle= Area of Parallelogram.
Therefore Area of parallelogram = 1/2 Area of triangle.
Which is :- 2*Area of any one triangle= Area of Parallelogram.
Therefore Area of parallelogram = 1/2 Area of triangle.
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