Question

if a triangle has a base of 4/7/3 cm and its height is 4/11/3 cm find its area
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Answer 1

Step-by-step explanation:

area of traingle 1/2(base ×height)

so we get

8/38.5/4.5

Answer 2

ANSWER:

$\huge \sf area = 0.93 {cm}^{2}$

given

$base = \dfrac{4}{ \frac{7}{3} } = \dfrac{12}{7} \: cm$

$height = \dfrac{4}{ \frac{11}{3} } = \dfrac{12}{11} cm$

METHOD:

in the attachment

FORMULA:

$\sf \boxed {area \: of \: triangle \: = \frac{1}{2} \times base \times height}$

so when we substitute the values in the equation we get

$area = \frac{72}{77} = 0.93 {cm}^{2}$