Question

If a triangle has its sides in the ration 2:3:5 and value of s is 35 cm, hen what is the
perimeter of the triangle​

Answer 1

Answer:

let x be the common multiple

\begin{gathered}35 = \frac{2x + 3x + 5x}{2} \\ 70 = 10x \\ x = 7\end{gathered}

35=

2

2x+3x+5x

70=10x

x=7

perimeter of triangle = a+b+c

\begin{gathered}2x + 3x + 5x \\ 2 \times 7 + 3 \times 7 + 5 \times 7 \\ 14 + 21 + 35 \\ 70\end{gathered}

2x+3x+5x

2×7+3×7+5×7

14+21+35

70

I think it's helpful to you

Answer 2

Step-by-step explanation:

s =a +b+c / 2

2x +3x+ 5 x /2 =35

10x =70

x=u

therefore

sides are

2x=2 x 7=14

3x=3 x 7=21

5x=5 x 7=35

perimeter of triangle = sum of three side

=14+21+35

=70