If a triangle has perimeter 48 and one of its side is 21 then find the small side
Answers
Answered by
1
(1) Given that the sides of a triangle are 3x,4x,5x.
Given that perimeter of a triangle = 48cm.
3x + 4x + 5x = 48
12x = 48
x = 4.
Then the sides of a triangle are:
3x = 3 * 4 = 12
4x = 4 * 4 = 16
5x = 5 * 4 = 20
We know that semi-perimeter of a triangle s = a + b + c/2
= (12 + 16 + 20)/2
= 48/2
= 24.
We know that Area of a triangle =
=
=
=
= 96 cm^2.
(2) Given sides of the triangle are 3x,5x,7x
Given perimeter of a triangle = 300m.
3x + 5x + 7x = 300
15x = 300
x = 20.
Then the sides of the triangle are
3x = 3 * 20 = 60
5x = 5 * 20 = 100
7x = 7 * 20 = 140.
We know that semi-perimeter of a triangle s = (a + b + c)/2
= (60 + 100 + 140)/2
= 300/2
= 150m
We know that Area of a triangle =
=
=
=
=
=
=
=
=
=
= 1500 * 1.732
= 2598.
Hope this helps!
Given that perimeter of a triangle = 48cm.
3x + 4x + 5x = 48
12x = 48
x = 4.
Then the sides of a triangle are:
3x = 3 * 4 = 12
4x = 4 * 4 = 16
5x = 5 * 4 = 20
We know that semi-perimeter of a triangle s = a + b + c/2
= (12 + 16 + 20)/2
= 48/2
= 24.
We know that Area of a triangle =
=
=
=
= 96 cm^2.
(2) Given sides of the triangle are 3x,5x,7x
Given perimeter of a triangle = 300m.
3x + 5x + 7x = 300
15x = 300
x = 20.
Then the sides of the triangle are
3x = 3 * 20 = 60
5x = 5 * 20 = 100
7x = 7 * 20 = 140.
We know that semi-perimeter of a triangle s = (a + b + c)/2
= (60 + 100 + 140)/2
= 300/2
= 150m
We know that Area of a triangle =
=
=
=
=
=
=
=
=
=
= 1500 * 1.732
= 2598.
Hope this helps!
Similar questions