Math, asked by siscor5521, 1 year ago

If a triangle has perimeter 48 and one of its side is 21 then find the small side

Answers

Answered by angleanu
1
(1) Given that the sides of a triangle are 3x,4x,5x.

Given that perimeter of a triangle = 48cm.

3x + 4x + 5x = 48

12x = 48

x = 4.

Then the sides of a triangle are:

3x = 3 * 4 = 12

4x = 4 * 4 = 16

5x = 5 * 4 = 20


We know that semi-perimeter of a triangle s = a + b + c/2

= (12 + 16 + 20)/2

= 48/2

= 24.


We know that Area of a triangle =

=

=

=

= 96 cm^2.




(2) Given sides of the triangle are 3x,5x,7x

Given perimeter of a triangle = 300m.

3x + 5x + 7x = 300

15x = 300

x = 20.

Then the sides of the triangle are

3x = 3 * 20 = 60

5x = 5 * 20 = 100

7x = 7 * 20 = 140.

We know that semi-perimeter of a triangle s = (a + b + c)/2

= (60 + 100 + 140)/2

= 300/2

= 150m


We know that Area of a triangle =

=

=

=

=

=

=

=

=

=

= 1500 * 1.732

= 2598.



Hope this helps!
Similar questions