If a triangle has two equal side and each 4m less than three times the third side, find the dimensions of the triangle if perimeter is 55m
Answers
Answered by
3
Let the first side be x
Second equal side=3x-4
Third equal side=3x-4
Perimeter=55m
So, the equation formed-
x+3x-4+3x-4=55
7x-8=55
7x=55+8
x=63/7=9
First side is 9m
Second side is 9*3-4=24m
Third side is also 24m
Hope this helps....
Second equal side=3x-4
Third equal side=3x-4
Perimeter=55m
So, the equation formed-
x+3x-4+3x-4=55
7x-8=55
7x=55+8
x=63/7=9
First side is 9m
Second side is 9*3-4=24m
Third side is also 24m
Hope this helps....
IshanS:
wrong calculation!
Answered by
7
Hi there!
Given :-
Triangle has two equal side and each 4m less than three times the third side.
Let us consider the third side to be = x
n' length of other two sides each = 3x - 4 ---( Given )
ATQ,
3x - 4 + 3x - 4 + x = 55
7x - 16 = 55
7x - 16 + 16 = 55 + 16
7x = 63
x = 63 / 7
x = 9
Hence, The required answer is :-
♦ Length of third side = x = 9
♦ Length of other two sides each = 3x - 4 = 3(9) - 4 = 27 - 4 = 23
Hope it helps! :)
Given :-
Triangle has two equal side and each 4m less than three times the third side.
Let us consider the third side to be = x
n' length of other two sides each = 3x - 4 ---( Given )
ATQ,
3x - 4 + 3x - 4 + x = 55
7x - 16 = 55
7x - 16 + 16 = 55 + 16
7x = 63
x = 63 / 7
x = 9
Hence, The required answer is :-
♦ Length of third side = x = 9
♦ Length of other two sides each = 3x - 4 = 3(9) - 4 = 27 - 4 = 23
Hope it helps! :)
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