Question

If a triangle is 17 inches across the hypotenuse, and is 8 inches long, then how wide is it?
17
19
15
13

Answer 1

Answer:

Ab^2=bc^2+ac^2

8^2= bc^2+ 17^2

64=bc^2+ 289

Bc^2 = 289-64

Bc^2 =225

Bc=15

Step-by-step explanation:

Answer 2

Answer:

15

Step-by-step explanation:

Pythagoras theorem= H^2=p^2+b^2

=(17)^2=(8)^2+b^2

=289=64+b^2

=289-64=b^2

=225=b^2

=√225=b

=15=b

hope it's clear