If a triangle is 35 sq unit with vertices of (2,-6) (5,4) and (k,4) then find the value of k
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Answer :-
k = -8.5 unit
Given :-
(x1,y1) > (2,-6)
(x2,y2) > (5,4)
(x3,y3) > (k,4)
A = 35sq units
A = {x1(y2-y3) - x2(y1-y3) + x3(y1-y2)} = 35
{2(4-4) - 5(-6-4) + k(-6-4)} = 35
0 - 5(-10) + k (-10) = 35
-50 -10k = 35
10k = -85
k = -8.5
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