Question

If a trolley starts from rest with an acceleration of 2cm/s², Find the velocity of the body after 3s​ec.
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Answer 1

Given :-

☞$\:\begin{cases}\sf\red{Trolley \ starts \ from \ rest}\\\sf\orange{Acceleration\: ( a ) \:= \:2 cm/s^2 }\\\sf\purple{Time \ interval \ (t) \ = \ 3 sec }\end{cases}$

To find :-

• $\bf\green{Velocity}$ after 3 seconds

Solution :-

• We know that, trolley starts from rest.

$\therefore\:\bf\purple{Initial \ velocity \ (u) \ = \ 0m/s}$

$\to\:\:\sf{Acceleration \ = \ 2cm/s^2}$

$\to\:\:\sf{Acceleration \ = \ \bigg(\dfrac{2}{100}\bigg)\:m/s^2}$

$\to\:\:\sf{Acceleration \ = \ {\bf{0.02m/s^2}}}$

Using 1st equation of motion

$\to\:\:\sf{v = u + at}$

$\to\:\:\sf{v = 0 + (0.02\times 3)}$

$\to\:\:\sf{v = 0.06m/s}$

Hence,

$\small\star\:{\boxed{\rm{\red{Velocity \ of \ body \ after \ 3 \ seconds \ is \ {\bf{\red{0.06 m/s}}}}}}}$

Answer 2

Answer:

velocity after 3 sec= 6cm/s

Explanation:

v=final velocity

u=initial velocity =0

a=2cm/s^2

t=3sec

v=u+at

= 0+2*3

=6cm/s