If a truck is moving with velocity 40
km/hr applies brakes to save a child
at 25 m standing from the point from
where brake is applied. If the time
taken to stop the truck is 2 sec. Will
the truck kill the child?
Answers
Hope it helps you to understand it easily.................
Explanation:
Here, V(Final velocity)=0 m/s(truck stops)
, U(initial velocity)=40Km/h
=40×5/18
=200/18
=100/9m/s
Time(t)=2 seconds
Acceleration(a)=(V-U)/t
=(0-100/9)/2
= -100/9×1/2
= -100/18
= -50/9m/s^2
according to the equations of motion,
=> S=ut+1/2at^2
Here,S=Distance travelled
=> S=100/9×2+1/2×(-50/9)×2^2
=> S=200/9+1/2×(-50/9)×4
=> S=200/9+(-25/9)×4
=> S=200/9+(-100/9)
=> S=200/9+(-100/9)
=> S=100/9
=> S=11.11metres
Hence,as the truck will only travel 11.11 metres the truck will not kill the child .