Physics, asked by shinchan2734, 1 month ago

if a tuning fork completes 300 vibration in 1.5 sec the the
(a) frequency of the tuning fork is 200 Hz.
(b) time period of the tuning fork is 20 sec .
( c) frequency of the tuning fork is 0.005 Hz .
(d) time period of the tuning fork is 0.005 sec.​

Answers

Answered by akashbindjnvg
2

(a) frequency of the tuning fork is 200 Hz.

d) time period of the tuning fork is 0.005 sec.

Explanation:

Given ⤵

  • A tuning fork completes 300 vibration in 1.5 sec the the

To find ⤵

  • Frequency and Time period

Solution⤵

Frequency:-

is the number of vibration per second.

➡f=\frac{300}{1.5}Hz

➡f=\frac{3000}{15}Hz

➡f=200Hz

Time period:-

The time taken for one complete one ocilation.

T=1/f

➡T=1/200

➡T=0.005sec

✅Hence,Both option (a) frequency of the tuning fork is 200 Hz and d) time period of the tuning fork is 0.005 sec is correct.

✍akashbindjnvg✍

Hope this is helpful to you!

Similar questions