if a tuning fork completes 300 vibration in 1.5 sec the the
(a) frequency of the tuning fork is 200 Hz.
(b) time period of the tuning fork is 20 sec .
( c) frequency of the tuning fork is 0.005 Hz .
(d) time period of the tuning fork is 0.005 sec.
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(a) frequency of the tuning fork is 200 Hz.
d) time period of the tuning fork is 0.005 sec.
Explanation:
Given ⤵
- A tuning fork completes 300 vibration in 1.5 sec the the
To find ⤵
- Frequency and Time period
Solution⤵
Frequency:-
is the number of vibration per second.
➡f=
➡f=
➡f=200Hz
Time period:-
The time taken for one complete one ocilation.
T=1/f
➡T=1/200
➡T=0.005sec
✅Hence,Both option (a) frequency of the tuning fork is 200 Hz and d) time period of the tuning fork is 0.005 sec is correct.
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