Question

If  a  TV  of  rating  100W  is  operated  for  6  hrs
per  day,  find  the  number  of  units  consumed
in  any  leap  year,  

MSCERT Class 10 General Science Ch4 The Electric Spark

Answer 1

100/1000=1/10kwmultiplied by6hrs=3/5kwh
no of units consume in a leap year=3/5multiplied366=1032/5units

Answer 2

Answer:

Explanation:

Given: Power (P) = 100 W

P = 100

1000

kW = 1

10

kW

Time (t) = 6 × 366 = 2196 hrs

To find: Unit consumed = ?

Formula: H = P × t

Solution: H = P × t

    H = 1

10

× 2196

H = 219.6 kWh

Ans. Number of units consumed is 219.6