Question

If a TV rating 100w is operated for 6h per day find number of unit comsum in any leap year

Answer 1

unit consumed is 219.6

Answer 2

Answer:

Explanation:

Given: Power (P) = 100 W

P = 100

1000

kW = 1

10

kW

Time (t) = 6 × 366 = 2196 hrs

To find: Unit consumed = ?

Formula: H = P × t

Solution: H = P × t

    H = 1

10

× 2196

H = 219.6 kWh

Ans. Number of units consumed is 219.6