if a two digit number digit in units place is twice the digit in tens place if 27 is added to it digit are reversed find the number
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Answer :-
Number is 36.
Explanation :-
Let the digit in tens place be x
Digit in units place = Twice the digit in tens place = 2(x) = 2x
Number formed = 10(digit in tens place) + digit in units place = 10(x) + 2x = 10x + 2x = 12x
Number formed when digits are reversed = 10(digit in units place) + digit in tens place = 10(2x) + x = 20x + x = 21x
Given
Number formed + 27 = Number formed when digits are reversed
⇒ 12x + 27 = 21x
⇒ 27 = 21x - 12x
⇒ 27 = 9x
⇒ 27/9 = x
⇒ 3 = x
⇒ x = 3
Number = 12x = 12(3) = 36
∴ the number is 36.
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