Question

If a two-digit number is added to the number obtained by reversing the order of its digits, then the sum will always by divisible by__________, thus leaving the remainder 0.
please give me varified answer​

Answer 1

Step-by-step explanation:

solution of this question is 11

Answer 2

Answer:

Given :-

\large \sf \bullet \: \dfrac{2 - 9z}{17 - 4z} = \dfrac{4}{5} ∙

17−4z

2−9z

=

5

4

Solution :-

On cross multiplication

\large \sf \: 4(17 - 4z) = 5(2 - 9z)4(17−4z)=5(2−9z)

\large \sf \: 68 - 16z = 10 - 45z68−16z=10−45z

\large \sf \: 16z - ( - 45z )= 68 - 1016z−(−45z)=68−10

\large \sf \: 29z = - 5829z=−58

\large \sf \: z \: = \dfrac{ - 58}{29} z=

29

−58

{ \textsf {\textbf{\pink{ \underline{z = - 2}}}}}

z = - 2

Ans. For upper question