Math, asked by gauravkumar0, 1 year ago

If a two-digit number is k times the sum
of its digits. If the number formed by
interchanging the digits is m times the
sum of the digits, then the value of m is

Answers

Answered by eshankharya
7

Answer:

I think it is 11 - k

Step-by-step explanation:

Let's say that initially the tens digit is a and units digit is b

ATQ,

10a + b = k(a+b) ............................. (i)

After reversing:

10b + a = m(a+b) ............................. (ii)

Adding (i) and (ii)

11a + 11b = k(a+b) + m(a+b)

11(a+b) = (m + k)(a+b)

11 = m+k                            [Dividing both sides by a+b]

m = 11 - k

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