If a two-digit number is k times the sum
of its digits. If the number formed by
interchanging the digits is m times the
sum of the digits, then the value of m is
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Answer:
I think it is 11 - k
Step-by-step explanation:
Let's say that initially the tens digit is a and units digit is b
ATQ,
10a + b = k(a+b) ............................. (i)
After reversing:
10b + a = m(a+b) ............................. (ii)
Adding (i) and (ii)
11a + 11b = k(a+b) + m(a+b)
11(a+b) = (m + k)(a+b)
11 = m+k [Dividing both sides by a+b]
m = 11 - k
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