if A union B is equal to A intersection B then proof A is equal to B
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let x∈A then x∈A∪B
since , A∪B=A∩B
x∈A∩B
So, x∈B
i.e., if an element belongs to set A, then it must belong to set B also.
∴A⊂B
Similarly, if y∈B then, y∈A∪B
Since A∪B=A∩B
y∈A∩B
So, y∈A
∴ if y∈B
then y∈A
A⊂A
from (i) and (ii)
A⊂B and B⊂A
thus A=B
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