Question

If a unit charge experiences a force of 100N at a point then electric field intensity will be

Answer 1

Given ,

Charge (q) = 1.6 × 10^(-19) C

Force (f) = 100 N

As we know that , the force per unit charge is called electric field intensity

$\boxed{ \tt{Electric \: field \: (E) = \frac{f}{q} }}$

Thus ,

E = 100/1.6 × 10^(-19)

E = 6.25 × 10^(20) N/c

Hence , the electric field intensity will be 6.25 × 10^(20) N/c