If a unit vector is represented by 0.5i +0.25 j+ ck, then the value of c, is
(1) 1
(2) 10.71 . (3) 20.01
(4) 10.39
amber01:
I think question is wrong because value of c cant exceed 1
Answers
Answered by
1
heya there
your answer will be 1. 1
Answered by
0
unit vector magnitude is 1
So √( 0.5)^2 + (0.25)^2 + c^2 = 1
0.25 +0.0625 + c^2 = 1
0.3125 + c^2 = 1
c^2 =1-0.3125= 0.6875
c= 0.82
most closest option is 1)1
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