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If a unit vector is represented by 0.5i +0.25 j+ ck, then the value of c, is

(1) 1

(2) 10.71 . (3) 20.01

(4) 10.39

amber01:
I think question is wrong because value of c cant exceed 1

## Answers

Answered by

1

heya there

your answer will be 1. 1

Answered by

0

unit vector magnitude is 1

So √( 0.5)^2 + (0.25)^2 + c^2 = 1

0.25 +0.0625 + c^2 = 1

0.3125 + c^2 = 1

c^2 =1-0.3125= 0.6875

c= 0.82

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