Question

If a upon b equals to b upon c and a b c are not equal to zero then show that,
1. ( a+b+c ) ( b-c ) =ab-c sq

Answer 1

Answer:

(a+b+c)(b-c) = ab + b^2 +bc - ac - bc - c^2 =

ab + b^2 -ac - c^2.....(1)

.

It is given

(a/b) = (b/c)

cross multiply

b^2 = ac

put this value of b^2 in (1) you get

ab - c^2 proved