Question

if a value is increases twice successively by 20% than what is the net % increase in that value ?

Answer 1

let the value be x
increased value =
$x(1 + \frac{20}{100} )(1 + \frac{20}{100} )$
therefore increased value is =
$x( \frac{36}{25} )$
therefore net increase % =
$\frac{( \frac{36x }{25}) - x}{x} \times 100$
The answer is 44%