Question

If a variable takes discrete values x+4,x-7/2,x-5/2,x-3,x-2,x+1/2,x-1/2,x+5 then meadian is????

Answer 1

Answer:

Median of a data set is that value in data set which is in the middle.

If number of values in data set is even , then median

$\frac{n^{th term}+(n+1)^{th term}}{2}$

If number of observation in the data set is odd, then median

  $=\frac{n}{2}$

As, the data set is, x+4,x-7/2,x-5/2,x-3,x-2,x+1/2,x-1/2,x+5.

Arranging the data set in ascending order, whatever the variable x will take the value, that is any real number

$x-\frac{7}{2},x-\frac{5}{2},x-3, x-2, x-\frac{1}{2},x+\frac{1}{2},x+4, x+5$

As, number of observation is even that is 8,

So , Median

$=\frac{4^{th term}+5^{th term}}{2}\\\\=\frac{x-2+x-\frac{1}{2}}{2}\\\\=\frac{2x-\frac{5}{2}}{2}\\\\=x-\frac{5}{4}$

Answer 2

Step-by-step explanation:

Given data's are, x+4, x−

2

7

, x−

2

5

, x−3, x−2, x+

2

1

, x−

2

1

, x+5, (x>0)

Now arranging in ascending order, x−

2

7

, x−3, x−

2

5

, x−2, x−

2

1

, x+

2

1

,x+4, x+5

Hence required mean = mean of 4

th

and 5

th

term =x−

4

5

(Since number of terms are even.)