Question

if a varies directly with b^2 and a=9 when b=6 then the possible value of b when a=1 is

Answer 1

Answer:

nopr and I have to go back in touch soon about this and the following questions and when the following ad to mujhe pata h mujhe Laga ke pass

Answer 2

Step-by-step explanation:

Given, a varies directly with b^2.

=> a = k (b)^2 ....(1) (say k is some constant)

Now, when a=9, b=6

Then,equation 1 will give,

9 = k (6)^2

k=9/36 =1/4 ......(2)

Therefore, when a=1 , we will get 'b' as:

From 1 and 2, a = k(b)^2

=>1 = 1/4 × (b)^2

=>b^2 = 1/(1/4)

=>b^2 = 4

=>b = 2