If a varies inversely as b+2 and if a=8 when b =1.5,find a when b =5
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Given , a ∝ 1/b+2 .
a₁ /a ₂ =b₂+2 / b₁ +2 .
Given a₁ =8 , b₁ =1.5
b₂=5 .
8/a₂ = 5+2 / 1.5 +2
=> 8/a₂ = 7/3.5
=>8/a₂ = 2
=> a₂ =8/2
=> a₂ =4 .
Therefore,when b = 5 , then a =4
Hope it helps you !
a₁ /a ₂ =b₂+2 / b₁ +2 .
Given a₁ =8 , b₁ =1.5
b₂=5 .
8/a₂ = 5+2 / 1.5 +2
=> 8/a₂ = 7/3.5
=>8/a₂ = 2
=> a₂ =8/2
=> a₂ =4 .
Therefore,when b = 5 , then a =4
Hope it helps you !
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