If 'a ' varies inversely as t to the power 2 , and if a=2, when t=0.3, write formula for 'a ' in terms of 't'. plzz help with this one then what u'll say I'll do that only
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15. r is proportional to the sixth power of y 2 1.8 1.6 7.4 L.2 . ... + sin(zr.r) -2<x<2 D:-2< ;x<2. xl-l,xl0, -2<x<2 x+l -8 -4 35..4: 3.t, .... Y 0.3, 0.4, : ]x + 1 is t 9.a ...
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Answer:
Insufficient Data
Step-by-step explanation:
'a ' varies inversely as t to the power 2
this means
a ∝ 1/t²
=> a = k/t² + c
where k & c are constants
when t = 0.3 = 3/10
value of a = 2
=> 2 = k/(3/10)² + c
=> 2 = 100k/9 + c
=> 18 = 100k + 9c
there are two variables k & c and only one equation
so solution can not be found.
Insufficient Data
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