Question

If A varies jointly as B and the cube of C when A = 200 when B = 5 and C = 2. Find A when B =

6 and C = 3?​

Answer 1

Answer:

If a varies jointly as b and the cube of c

For joint variation, y varies jointly as x and z we use equation

y = kxz, where k is the constant of proportionality

Given : a varies jointly as b and the cube of c

So equation becomes

a = kbc^3a=kbc

3

a = 200 when b = 5 and c = 2. we use the given values and find out k

200 = k (5)(2)^3

200 = k (5)(2)^3200=k(5)(2)

3

200= 40k (divide by 40 on both sides)

k = 5

find a when b = 6 and c = 3 , k = 5

a=kbc

3

a = 5*6*(3)^3a=5∗6∗(3)

3

a = 810